x^2-4x+5ifx=5

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Solution for x^2-4x+5ifx=5 equation:


Simplifying
x2 + -4x + 5ifx = 5

Reorder the terms:
5fix + -4x + x2 = 5

Solving
5fix + -4x + x2 = 5

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '4x' to each side of the equation.
5fix + -4x + 4x + x2 = 5 + 4x

Combine like terms: -4x + 4x = 0
5fix + 0 + x2 = 5 + 4x
5fix + x2 = 5 + 4x

Add '-1x2' to each side of the equation.
5fix + x2 + -1x2 = 5 + 4x + -1x2

Combine like terms: x2 + -1x2 = 0
5fix + 0 = 5 + 4x + -1x2
5fix = 5 + 4x + -1x2

Divide each side by '5ix'.
f = i-1x-1 + 0.8i-1 + -0.2i-1x

Simplifying
f = i-1x-1 + 0.8i-1 + -0.2i-1x

Reorder the terms:
f = 0.8i-1 + i-1x-1 + -0.2i-1x

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